SET1- Aptitude online test - AGE problems

Then, Tharan's age cannot be determined.

If the ratio was 3 : 5, 'A' years ago. Then, 7A - 6A = 4 A = 4 Then, {( 40 - A)/(60 - A)}= (3/5) 5 (40 - A) = 3(60 - A) 2A = 20 A = 10 {Ans in decades : 1 }

Let the current age of Karthikh is A years Then, A+15 = 4(A – 15) Therefore A = 25

Condition : Naresh’s current age is A years and Abdul’s current age is B years. Then, based on the first condition, A - 10 = 3[B - 10] or, A - 3B = -20 ..(1) Here, Naresh's age after 10 years =(A + 10) years Abdul's age after 10 years = (B + 10) (A+10) = 2(B+10) or, A - 2B = 10 ..(2) Solving Eqn(1) & Eqn(2), we will get A = 70 and B = 30 Naresh's age = 70 years and Abdul's age = 30 years.

If the ages of Kumar, Hathim and Rahul 1 decade ago be 2A, 3A and 4A years correspondingly Then, (2A + 10) + (3A + 10) + (4A + 10) = 93 9A = 93-30 9A = 63 A = 7 Rahul's current age = (4A + 10) = 38 years.

Let Harsh's age 6 years back = A Then, Amith's age 6 years back = 32. Then 5/3 (A + 6 + 6) = (3A + 6 + 6) 5(A + 12) = 3 (3A + 12) 4A = 24 A = 6 Harsh's age today = (A + 6) years = 12 years

If the current ages of Karthikh and Prasath be 4A years and 3A years correspondingly. Then, 4A + 6 = 26 4A = 20 A = 5 Prasath's age = 3A = 15 years.

If the ages of daughter and father today by 'A' and '4A' years correspondingly. 4A + 20 = 2 (A+20) A = 10 years => 4A = 40 years. At the time of daughter's birth, father's Age 40 - 10 = 30 years old

Let their current ages are 4A, 7A and 9A years correspondingly. Then, (4A - 8) + (7A - 8) + (9A - 8) = 56 20A = 80 A = 4 Their current ages are 16 years, 28 years and 36 years correspondingly.

If current ages of Rahim and Thomas be 5A years and 4A years correspondingly Then, 5A + 3 = 11 4A + 3 = 9 9(5A + 3)=11(4A + 3) A = 6 Thomas's current age = 4A = 24 years.

Let, today's age of the daughter = ‘A’ years. Mom’s age today = 3A years After 10 decades, 3A + 10 = 29A + 10 => A = 10 years

Average * Subject Areas = Total Age So => 21 years x 22 numbers = 462 years ... (1) => 22 years x 23 numbers = 506 years ... (2) Therefore Lecturer’s age = Eqn(2) - Eqn(1) = 506 – 462 = 44 Years.

If A's age and B's age will be 6A years and 7A years correspondingly Then, 7A - 6A = 4 A = 4 Needed ratio = (6A + 4) : (7A + 4) = 28 : 32 = 7 : 8

Let, daughter’s current age is A years. Then, person’s current age = (A +24) years. (A + 24) + 2 = 2 (A + 2) A + 26 = 2A + 4 A = 22

Let Karthikh's age 10 years ago be A year His mother's age 1 decade ago = 4A (4A + 10) + 10 = 2 (A + 10 +10) 2A = 20 or A =10 Current age of Karthikh = (A + 10) = 20 years

Let the ages of X and Y 1 decade ago be A and 2A years correspondingly. Then, [ (A +10)/2A+10) ] = (3/4) 4 (A - 10) = 3(2A - 10) 2A = 10 A = 5 Therefore, Sum of theircurrent ages = (A + 10) + (2A + 10) = (3A + 20) = 35 years

Let Smirthi's age = A years So, Deepika's age = (A + 16) years Also, 3(A - 6) = A + 16 - 6 or, A = 14 Smirthi's age = 14 years and, Deepika's age = 14 + 16 = 30 years

Let, current age is A years. Then, 125% of (A - 10) = A and, 83(1/3)% of (A + 10) = A Therefore 125% of (A-10) = 83(1/3)% of (A+10) or, (5/4) (A - 10) =(5/6)(A+10) or, (5/4)A -(5/6)A = (50/6)+(50/4) or, (5A/12)= (250/12) or, A=50 years.

Let daughter's age = A. Then father's age = 2A 12 (A - 20) = (2A - 20) 10A = 220 A = 22 Father's current age = 44 years.

None of these